this code won't continue after checks if variable x integer or not. gives out valueerror, if x not int. how make program ignore error? i've tried invert statement so:
elif x isinstance(x, int): but then, if give integer, jumps else statement.
from tkinter import * root = tk() root.wm_title("inout") root.geometry('500x500') greetings = ["hello", "hello", "greetings", "greetings"] def out(event): x = ent.get() if x in greetings: lr.configure(text=x + ",\n there\n anything\n can do\n you?") elif x isinstance(x, int): if int(x) == 0: lr.configure(text="this 0") elif int(x) % 2 == 0: lr.configure(text="this number") elif int(x) % 2 != 0: lr.configure(text="this odd number") elif x "": lr.configure(text="well") else: print("closing") root.destroy() ent = entry(root) ent.grid(row=0, column=0, sticky=nw) lr = label(root, text="output") lr.grid(row=0, column=2, columnspan=2) btn = button(root, text="process") btn.grid(row=0, column=1, sticky=nw) btn.bind("<button-1>", out) root.mainloop()
i think might trying see if string integer. instead of if statement, use try/except block:
def is_int(x): try: x = int(x) return true except: return false put in code , use instead of call isinstance. now, if x integer, right you're asking if x (true or false), going return false. if x string turned integer, isinstance(x,int) never going return true if x converted int.
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