linux - remove row from tab delimited file using grep -v -

i have 1 tab delimited file column 1 being id , column 2 being information. i've second file list of ids need removed first file. when use grep, either copy of first file no changes or blank file using -v -f -f "file2.txt" flags/arguments. question is: how use file2.txt compare ids file1 eliminate rows file1 output file3.

awk 'begin{rs=">"}nr>1{sub("\n","\t"); gsub("\n",""); print rs$0}' $1 > fasta.tab  grep -f -f $2 fasta.tab -v >rmoutput.tab tr '\t' \n' <rmoutput.tab >rmoutput.fas echo runtime complete 

line 1: create tab-delim file input 1 line 2: check input 2 matches , remove tab-delim file line 3: recreate format of input 1 (for clarity)

edit: sample i/o

input 1 (tab-delim--after line 1):

id1    info1 id2    info2 id3    info3 id4    info4 id5    info5 

input 2 (ids deleted):

id2 id4 id5 

desired output (from line 2)

id1    info1 id3    info3 

awk 'nr==fnr{a[$0];next} !($1 in a)' input2 input1